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when detecting a new instance fails due to a duplicate entry, print both.

Natenom/support-murmur-13-1446181288462
Michael Ziegler 15 years ago
parent
commit
b779ab9cb8
  1. 24
      pyweb/mumble/management/server_detect.py

24
pyweb/mumble/management/server_detect.py

@ -16,6 +16,7 @@
import os, getpass
from django.db import DatabaseError
from django.conf import settings
from mumble import models
@ -123,12 +124,31 @@ def find_existing_instances( **kwargs ):
if v > 1:
print "Syncing Murmur instance... ",
instance.configureFromMurmur();
if v > 1:
print instance.name;
instance.save( dontConfigureMurmur=True );
try:
instance.configureFromMurmur();
except DatabaseError, err:
try:
# Find instances with the same address/port
dup = models.Mumble.objects.get( addr=instance.addr, port=instance.port )
except Mumble.DoesNotExist:
# None exist - this must've been something else.
raise err
else:
print "ERROR: There is already another server instance registered"
print " on the same address and port."
print " New Server Name:", instance.name
print " Address:", instance.addr
print " Port:", instance.port
print " Connection string:", instance.server.dbus
print "Duplicate Server Name:", dup.name
print " Address:", dup.addr
print " Port:", dup.port
print " Connection string:", dup.server.dbus
return False
# Now search for players on this server that have not yet been registered
if instance.booted:

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