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//! Transformation of complex data.
// The implementation is based on:
// http://www.librow.com/articles/article-10
use number::c64;
/// Perform the forward transform.
///
/// The number of points should be a power of two.
pub fn forward(data: &mut [c64]) {
let n = power_of_two!(data);
rearrange(data, n);
perform(data, n, false);
}
/// Perform the inverse transform.
///
/// The number of points should be a power of two.
pub fn inverse(data: &mut [c64], scaling: bool) {
let n = power_of_two!(data);
rearrange(data, n);
perform(data, n, true);
if scaling {
scale(data, n);
}
}
fn rearrange(data: &mut [c64], n: usize) {
let mut target = 0;
for position in 0..n {
if target > position {
data.swap(position, target);
}
let mut mask = n >> 1;
while target & mask != 0 {
target &= !mask;
mask >>= 1;
}
target |= mask;
}
}
fn perform(data: &mut [c64], n: usize, inverse: bool) {
use std::f64::consts::PI;
let sign = if inverse { 1.0 } else { -1.0 };
let mut step = 1;
while step < n {
let jump = step << 1;
let (multiplier, mut factor) = {
let delta = sign * PI / step as f64;
let sine = (0.5 * delta).sin();
(c64(-2.0 * sine * sine, delta.sin()), c64(1.0, 0.0))
};
for group in 0..step {
let mut pair = group;
while pair < n {
let match_pair = pair + step;
let product = factor * data[match_pair];
data[match_pair] = data[pair] - product;
data[pair] = data[pair] + product;
pair += jump;
}
factor = multiplier * factor + factor;
}
step <<= 1;
}
}
fn scale(data: &mut [c64], n: usize) {
let factor = 1.0 / n as f64;
for position in 0..n {
data[position] = data[position] * factor;
}
}