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Formatting

pull/16/head
andreimarcu 9 years ago
parent
commit
cf39a98cdd
  1. 50
      util.go

50
util.go

@ -8,6 +8,31 @@ import (
// from http://stackoverflow.com/a/31832326
var src = rand.NewSource(time.Now().UnixNano())
const letterBytes = "abcdefghijklmnopqrstuvwxyz1234567890"
const (
letterIdxBits = 6 // 6 bits to represent a letter index
letterIdxMask = 1<<letterIdxBits - 1 // All 1-bits, as many as letterIdxBits
letterIdxMax = 63 / letterIdxBits // # of letter indices fitting in 63 bits
)
func randomString(n int) string {
b := make([]byte, n)
// A src.Int63() generates 63 random bits, enough for letterIdxMax characters!
for i, cache, remain := n-1, src.Int63(), letterIdxMax; i >= 0; {
if remain == 0 {
cache, remain = src.Int63(), letterIdxMax
}
if idx := int(cache & letterIdxMask); idx < len(letterBytes) {
b[i] = letterBytes[idx]
i--
}
cache >>= letterIdxBits
remain--
}
return string(b)
}
var mimeToExtension = map[string]string{
"application/andrew-inset": "ez",
"application/applixware": "aw",
@ -777,28 +802,3 @@ var mimeToExtension = map[string]string{
"video/x-smv": "smv",
"x-conference/x-cooltalk": "ice",
}
const letterBytes = "abcdefghijklmnopqrstuvwxyz1234567890"
const (
letterIdxBits = 6 // 6 bits to represent a letter index
letterIdxMask = 1<<letterIdxBits - 1 // All 1-bits, as many as letterIdxBits
letterIdxMax = 63 / letterIdxBits // # of letter indices fitting in 63 bits
)
func randomString(n int) string {
b := make([]byte, n)
// A src.Int63() generates 63 random bits, enough for letterIdxMax characters!
for i, cache, remain := n-1, src.Int63(), letterIdxMax; i >= 0; {
if remain == 0 {
cache, remain = src.Int63(), letterIdxMax
}
if idx := int(cache & letterIdxMask); idx < len(letterBytes) {
b[i] = letterBytes[idx]
i--
}
cache >>= letterIdxBits
remain--
}
return string(b)
}
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